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Komok [63]
3 years ago
8

Laura bernett is 5 ft-4 inches tall. she stands 12 feet from a streetlight and casts a 9-foot-long shadow. how tall is the stree

tlight?
Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0
The ratio of the height (h) of the streetlight to its distance to the end of Laura's shadow is the same as the ratio of Laura's height to her distance from the end of her shadow.
.. h/(12+9) = 5'4"/9
.. h = (21/9)*5'4" = 12 4/9 feet
.. h = 12 ft 5 1/3 inches

The streetlight is 12 ft 5 1/3 inches tall.
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Calculate the value of x if 2x/3=8/5
Cloud [144]

Answer:

12/5 or 2⅖

Step-by-step explanation:

2x/3 = 8/5

2x = 3 × 8/5

2x = 24/5

x = 24/5 ÷ 2

x = 12/5

Or 2⅖

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3 years ago
Ari thinks the perfect milkshake has 3 ounces of caramel for every 5
tangare [24]

Answer:

A - They Have Too Much Caramel

Step-by-step explanation:

Ari likes 3 oz caramel for 5 scoops ice cream.

Freeze Zone makes 6 oz caramel with 8 scoops of ice cream.

Divide both amounts of Freeze Zone by 2.

6 oz caramel for 8 scoops of ice cream is the same ratio as

3 oz caramel for 4 scoops of ice cream.

Since Ari likes 3 oz caramel for 5 scoops ice cream,

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8 0
3 years ago
If the bird is directly above the fish, how far apart are they
jolli1 [7]

Answer:

0 length, the bird is touching the top of the fish

Step-by-step explanation:

7 0
3 years ago
Help me and u will get 100 points at the end
Lera25 [3.4K]

Answer:

x > 0 and y < 2

Step-by-step explanation:

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3 0
1 year ago
Read 2 more answers
Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab
Nastasia [14]

Answer:

1/12

Step-by-step explanation:

<u>Needed information</u>

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

The sum of the probabilities of all outcomes must equal 1

<u>Solution</u>

We are told that the probability that the counter is <em>not</em> black is 3/4.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>black by subtracting 3/4 from 1:

\sf P(counter\:not\:black)=\dfrac34

\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14

We are told that the probability that the counter is <em>not </em>white is 2/3.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>white by subtracting 2/3 from 1:

\sf P(counter\:not\:white)=\dfrac23

\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13

We are told that there are black, white and grey counters in the bag.  We also know that the sum of the probabilities of all outcomes must equal 1.  Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}

7 0
2 years ago
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