Approximately how many times greater is 9.75 * 10^6 than 1.25 * 10^2?

the sum of two numbers is 75. The second number is three less than twice the first. what is the larger number?

KatRina [158]

Answer:

49

Step-by-step explanation:

If the smaller number is

x

, then the larger number is

2

x

−

3

Explanation:

(

x

)

+

(

2

x

−

3

)

=

75

3

x

−

3

=

75

3

x

=

78

x

=

26

The numbers are 26 and 49.

5 0

2 years ago

a clothing store is having a sale of 30% off all dresses what is the discount on new price of the dress originally cost $90

Paul [167]

Answer:

$63

Step-by-step explanation:

30% of 90 is 27

90-27=63

8 0

3 years ago

T: 3(t + 3) + 5(3 + 2t) – 76 = 0

Setler [38]

Answer:

$\huge\boxed{\sf t = 4}$

Step-by-step explanation:

$\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}$

Hope this helped!

6 0

3 years ago

Read 2 more answers

An=an-1+6an-2 <br> n>2 a0=3 a1=6

Svetach [21]

$\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}$

Let the generating function for $a_n$ be

$A(x)=\displaystyle\sum_{n\ge0}a_nx^n$

Multiplying both sides by $x^{n-2}$

$a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}$

Summing both sides over the non-negative integers greater than or equal to 2 gives

$\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}$
$\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)$
$A(x)=\dfrac{3x+3}{1-x-6x^2}$
$A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}$

For $|x|$ , the two series converge to

$\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n$
$\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n$
$a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5$

5 0

3 years ago

48 ÷ (7 x 5 - 3 x 9) whoever gets the answer right, gets brainliest and 47 points. please help fast!

docker41 [41]

48 ÷ (7 x 5 - 3 x 9)

= 48 ÷ (35 - 27)

= 48 ÷ 8

= 6

Step-by-step explanation:

only half of your points for each answer ;)

5 0

2 years ago

Read 2 more answers