Answer:
x
=
(23
+
√
497 /
8)
, (23
−
√
497 /8)
x=5.66168710
Step-by-step explanation:
im too lazy. use math-way
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
Step-by-step explanation:
If she doubles the area of her lot, it should be 2x^2.
But how do you get that?
The answer is that the sides have now increased to √2x
How did I get that, and why did I choose it?
- The formula for a square's area is s^2
- If you want to double the area, it will be 2 s^2. Now what?
- Take the square root of 2s^2 which is √(2s^2).
- What that means is the side is now √2 s
1235 / 100
See 1235 as 1235.0, since we are dividing by 100, we have two zeros, so we move the decimal point in 1235.0 two places to the left.
12.35
What are the angles?
if all of them are below 90 degrees, it is acute.
if one angle is 90 degress, it is right
if one angle is more than 90 degrees, it is obtuse