A ray is a line with an end hope this helps
Answer:
x=133 y=-25
Step-by-step explanation:
I'll do both ways for you. So let's start with Substitution:
With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.
x + 2y = 83 & x + 5y = 8
Solve for x.
x = 83 - 2y & x = 8 - 5y
Once you have solved for x, set each equation equal to one another and solve for y now.
83 - 2y = 8 - 5y
Isolate all variables to one side:
83 = 8 - 3y
Now subtract the 8 to fully isolate the y variable:
75 = -3y
Divide by -3:
-25 = y Now that you have your first variable, plug it into one of the original equations and solve for x.
x + 2(-25) = 83
x - 50 = 83
x = 133
Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:
Put each equation on top of one another and subtract:
x + 2y = 83
- (x + 5y = 8)
The x's will cancel out:
(x - x) + (2y - 5y) = (83 - 8)
Simplify:
-3y = 75
Solve for y
y = -25
Then, plug y = -25 into one of the original equations:
x + 5(-25) = 8
Solve for x:
x - 125 = 8
x = 133
Hope this helps!
Answer:
1. 116 m
2. 60 cm
Step-by-step explanation:
1. The total area is 12*10 m, or 120 m. The area of the non-shaded region is 7*2 m, or 14. Subtract 14 from 120 to get 116.
BTW the side 12 looks like it is less than the 10, the question is not lengthed properly, just saying
2. A bit trickier, divide the question into 2 parts, a triangle and rectangle.
The rectangle is 12*4 cm, or 48 cm, the triangle is 12 - 3 - 3 = 6 and 8 - 4 = 4
So we use 6 and 4. The area of a triangle is 1/2b * h, half of the base times the height, the base is 6 cm, and the height is 4 cm, 1/2(6) * 4 = 3*4 = 12 cm
48 + 12 = 60 cm
All real numbers are correct! Hope that helps.
The answer is x = 0
To find this we must first find the length of IJ, Since IK is equal to 13 and JK is equal to 6, we can subtract to find the value of IJ.
IJ = IK - JK
IJ = 13 - 6
IJ = 7
Now, we know the value of HJ in terms of x, as we do the value of HI. So, we can add HI to IJ, which we just found and set equal to HJ
HJ = HI + IJ
2x + 15 = x + 8 + 7 ----> Simplify
2x + 15 = x + 15 -----> Subtract 15
2x = x ----> Subtract x
x = 0
