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Delvig [45]
3 years ago
5

Determine if the following equations form a perpendicular line or not

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0
  • Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.

If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2

<h2>6.</h2>

Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation: -5y=-2x+8

Next, divide both sides by -5 and your slope-intercept form is y=\frac{2}{5}x+\frac{8}{5}

Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>

<h2>7.</h2>

It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:

6x-3y=15 \\-3y=-6x+15\\y=2x-5\\\\2x+4y=-12\\4y=-2x-12\\y=-\frac{1}{2}x-3

Now since 2 <em>is</em> the negative reciprocal of -1/2, <u>these lines are perpendicular.</u>

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