Ask question

Ask question

All categories

3 years ago

13

2×x×3×y

\times 3 \times y" alt="2 \times x \times 3 \times y" align="absmiddle" class="latex-formula">

1 answer:

Zigmanuir [339]3 years ago

7 0

Answer:

6xy

Step-by-step explanation:

You might be interested in

A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing 104 pounds requires

sergeinik [125]

Answer:

223

Step-by-step explanation:

i think : )

7 0

2 years ago

A grocer buys food from three suppliers. the suppliers deliver every five days, six days, and seven days. all three came today.

Brilliant_brown [7]

Today is actually the 210th day. They will meet again in 209 days (the 210th is the day they deliver together so I don't count it, but you can totally count it if you want to)

6 0

3 years ago

John ran 6 2/3 miles last week he ran 1 1/3 miles each day how many days did he run

Murljashka [212]

$6\frac{2}{3} = \frac{3(6) + 2}{3} = \frac{20}{3} miles$

$1\frac{1}{3} = \frac{3(1) + 1}{3} = \frac{4}{3} miles/day$

$\frac{20}{3} miles$ ÷ $\frac{4}{3} miles/day$

= $\frac{20(miles)}{3}$ * $\frac{3(days)}{4 (miles)}$

= $\frac{20(3) days}{3(4)} = \frac{20 days}{4} = 5 days$

Answer: 5 days

4 0

3 years ago

X two the 2 power =144

Alina [70]

The answer to your question is 12

4 0

3 years ago

Read 2 more answers

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago