Answer:
d=16t squared
Step-by-step explanation:
0,-2
4,4
2,0
3,5
Step-by-step explanation:
that was my answer
Answer:
20,9
Step-by-step explanation:
this is how I did=x=1st, y=2nd; x=4y-16 and x+y=29; thus 4y-16+y=29; 5y-16=29; 5y=45; y=45/5=9, once you know y=9, put in equation, 4y-16=×, (4*9)-16=x, 36-16=x, 20=x
a.
×
A
b.
×
A
c.
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

×
A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

×
A
C. V= 12V
1/R =
=
× 
R =
= 310. 56 Ω

A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
brainly.com/question/14296509
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Answer:
All you need to do is find a common denomianatorand then solve from least to greatest hope this helps!
Step-by-step explanation: