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3 years ago

What is -2/5 as y=mx=b form or into slope intercept form

1 answer:

5 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ -5}} &,&{{ -1}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ -5}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-5-(-1)}{5-(-5)}\implies \cfrac{-5+1}{5+5}\implies \cfrac{-4}{10}
\\\\\\
 -\cfrac{2}{5}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=-\cfrac{2}{5}[x-(-5)]
\\\\\\
y+1=-\cfrac{2}{5}(x+5)\implies y+1=-\cfrac{2}{5}x-\cfrac{2}{\underline{5}}\cdot \underline{5}\implies y+1=-\cfrac{2}{5}x-2
\\\\\\
y+1-1=-\cfrac{2}{5}x-2-1\implies y=-\cfrac{2}{5}x-3$

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Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer

Y_Kistochka [10]

Answer:

$x_2=x_1$

Step-by-step explanation:

We were given the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

This line is vertical if the denominator is zero.

That is when $x_2-x-1=0$

This implies that;

$x_2=x_1$

Justification;

When $x_2=x_1$ , then, the line passes through;

$(x_1,y_1)$ and $(x_1,y_2)$

The slope now become

$m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}$

The equation of the line is

$y-y_1=\frac{y_2-y_1}{0}(x-x_1)$

This implies that;

$0(y-y_1)=(y_2-y_1)(x-x_1)$

$0=(y_2-y_1)(x-x_1)$

$\frac{0}{y_2-y_1}=(x-x_1)$

$0=(x-x_1)$

$x=x_1$ ... This is the equation of a vertical line.

3 0

3 years ago

What facts are required in order to conclude that m∠ADE = m∠ABC?

mariarad [96]

Answer:

The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))

∴ (sin(m∠ADE)) = (sin(m∠ABC))

m∠ADE) = m∠ABC).

3 0

3 years ago

The first three terms of an arithmetic progression are m,12 and n . Find the value of m+n

Vera_Pavlovna [14]

<h3>Answer: 24</h3>

===========================================

Explanation:

There are a few approaches. Here's one way to solve.

Let d be the common difference between the terms.

We add d to each term of this arithmetic sequence to get the next term.

First term = m
Second term = 12 = m+d
Third term = n = (m+d)+d = m+2d

Focusing on the second equation, we can solve for d like so

m+d = 12

d = 12-m

This is then plugged into the third equation

n = m+2d

n = m+2(12-m)

n = m+24-2m

n = 24-m

Therefore,

m+n = m+(24-m) = 24

It turns out that it doesn't matter what m and n are because m+n is always equal to 24 in this case.

-----------------

A more concrete example:

Let's say m = 2. We won't set up n just yet but we'll be able to compute it fairly soon.

Since m = 2, this means d = 12-m = 12-2 = 10. This is the gap between adjacent or neighboring terms.

If d = 10, then the third term must be n = 12+d = 12+10 = 22

We can then see that m+n = 2+22 = 24

-----------------

I'll do another example:

m = 5

d = 12-m = 12-5 = 7

n = 12+d = 7 = 19

m+n = 5+19 = 24

Whenever in doubt, or if you get stuck, it helps to come up with actual numeric values to hopefully clear things up.

-----------------

An alternative way to get the answer:

Let's try to determine what m+n is actually saying. We have 12 right in the middle of the first term (m) and third term (n). Because the gap between the numbers is the same (that being d), we know that 12 is the midpoint of m and n. It might help to draw out a number line to see what's going on.

The midpoint of m and n is (m+n)/2

Set this equal to 12 and isolate the "m+n"

(firstTerm+thirdTerm)/2 = second term

(m+n)/2 = 12

m+n = 2*12

m+n = 24

So in general, if the first three terms of the arithmetic sequence are m, k, n, then m+n = 2k.

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3 years ago

Limit as x approaches infinity: 2x/(3x²+5)

Nonamiya [84]

$\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\implies \cfrac{\lim\limits_{x\to \infty}~2x}{\lim\limits_{x\to \infty}~3x^2+5}$

now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

now, we could just use L'Hopital rule to check on that.

$\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}$

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.

5 0

3 years ago

What is a factor? _____________________________________________

andriy [413]

Answer: What is a factor?

A factor is a a divisor of an integer n, also called a factor of n, is an integer m that may be multiplied by some integer to produce n. In this case, one also says that n is a multiple of m. An integer n is divisible by another integer m if m is a divisor of n; this implies dividing n by m leaves no remainder.

Step-by-step explanation: Why can’t certain expressions be factored?

Because there are no common factors other than 1 the constants cannot be factored. And, because there is no x in the second term (10), we cannot factor an x out of the two terms.

4 0

3 years ago

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