Solve the equation shown:<br> 2.5x + 18 = 3.5%

M(12, 1) is the midpoint of DG. If D is at (6, 5), then where is G?

sukhopar [10]

Answer:

18, -3

using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2

4 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago

Please help!!!

abruzzese [7]

1)51 2)91 3)79 :)))))0

4 0

2 years ago

consider the following equation x+4/x-6+3/2x+5=7 What are the constraints on x? Select all that apply.

kirill115 [55]

Don’t really pay attention to the x .

4 0

3 years ago

The rules for an essay contest say that entries can have 500 words with an absolute deviation of at most 30 words. Write and sol

cupoosta [38]

Answer:

470<x<530

Step-by-step explanation:

Let x be number of acceptable words

|x-500|<300

we write absolute value inequality representing the acceptable number of words, given the fact that absolute deviation is at most 30 words

-30<x-500<30

500-30<x-500+500<30+500

470<x<530.

8 0

3 years ago

Read 2 more answers

Solve the equation shown: 2.5x + 18 = 3.5% - 4