C because 6 is being distributed into 10 and 3. It couldn’t be D because 6 comes after 10 and 3 which wouldn’t be distributing into them.
First divide both sides of the equation by -3, then add 3x to both sides of the equation.
-3x + y = -1
y = 3x + 1
AB = 7 1/2
BC = 2 1/4
DE = 1 1/4
AB = GH + EF + CD
AH + FG = DE + BC
The perimeter is AB + BC + CD + DE + EF + FG + GH + HA.
AB + BC + CD + DE + EF + FG + GH + HA =
= AB + BC + DE + AB + DE + BC =
= 2AB +2BC +2DE =
= 2 · 7 1/2 + 2 · 2 1/4 + 2 · 1 1/4 =
= 15 + 4 2/4 + 2 2/4 =
= 15 + 4 1/2 + 2 1/2 =
= 19 1/2 + 2 1/2 =
= 22 [m]
It is obvious that Triangle BCD is congruent to Triangle EFG. EFG is twice the size of BCD.
Put the lengths into the pythagorean theorem equation. (the longest side is the hypotenuse)
So for Triangle BCD
3^2+b^2=5^2
(3×3)+b^2=(5×5)
9+b^2=25
So what plus 9 equals 25?
16
the square root of 16 is 4 so 4^2=16
9+16=25
Now since we know that Triangle EFG is twice the size of BCD remake the equation but the numbers will be:
6^2+8^2=10^2
Now check
(6×6)+(8×8)=(10×10)
36+64=100
100=100
So for Triangle EFG X=8
Answer:
2/3
Step-by-step explanation:
Given that a six sided die with sides labelled with numbers 1,2,3,4,5 and 6 is rolled once.
Since die is said to be equally likely for each number, die is unbiased
P(1) = P(2)=...=P(6) = 1/6
For a number greater than 2, we must not include 2 and hence numbers can be 3 or 4 or 5 or 6
Probability of rolling a number >2 = Probability of rolling 3 or 4 or 5 or 6
= P(3)+P(4)+P(5)+P(6)
= 1/6+1/6+1/6+1/6
=4/6
=2/3
Required probability = 2/3