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tia_tia [17]
3 years ago
9

Every kid in Mr. Levans's 3rd grade class made a valentine for every kid in the class, including him- or herself. If the class m

ade a total of 484 valentines, how many kids are in the class?
Mathematics
2 answers:
shtirl [24]3 years ago
5 0

Let the total number of kids in Mr. Levans' 3rd grade class be x.

We know that each kid in the class made a Valentine for every kid in the class, including himself or herself.

So, the first kid made x Valentines. Likewise, the second kid too made x Valentines. If we go on so on and so forth, we will note that even the last, or the x^{th} kid made x Valentines too. Thus, this way we know that every kid made x Valentines.

Therefore, the total number of Valentines made are x\times x. It is given in the question that the number of Valentines made is 484.

Therefore, from the above information we conclude that:

x\times x=x^2=484

To find x we will have to take the square root of both sides. Which will give us:

\sqrt{x^2}=\sqrt{484}

x=22

Thus, the number of kids in the class is 22.


Assoli18 [71]3 years ago
3 0
I would say 22 i first looked at amount of average kids in a class then tried every number close. 484/22=22
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102 mg

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Which shows the phrase "the product of a number and 3" as a variable expression?
JulijaS [17]

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<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>

The word phrase is given as:

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Represent the number with z

So, the word phrase can be rewritten as:

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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
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Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago
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