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mojhsa [17]
3 years ago
14

Trigonometry

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

3 + 2sqrt(3)/3

Step-by-step explanation:

sin(30) = ½

cosec(30) = 2

sin(60) = sqrt(3)/2

cosec(60) = 2/sqrt(3) or 2sqrt(3)/3

sin(90) = 1

cosec(90) = 1

2 + 2sqrt(3)/3 + 1

3 + 2sqrt(3)/3

quester [9]3 years ago
4 0

Answer:

\frac{9 + 2 \sqrt{3} }{3} \\

Step-by-step explanation:

\cosec(30)  +  \cosec(60)  +  \cosec(90)  \\   \\  = 2 +  \frac{2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3 }  + 2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3}  + 2 +  \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \\  \\  = \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{9 + 2 \sqrt{3} }{3}

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Point B ∈ |AC| so that AB:BC=2:1. Point D ∈ |AB| so that AD:DB=3:2. Find AD:DC
grigory [225]

Answer:

5:4

Step-by-step explanation:

If point B divides the segment AC in the ratio 2:1, then

AB=2x units and BC=x units.

If point D divides the segment AB in the ratio 3:2, then

AD=3y units and DB=2y units.

Since AD+DB=AB, then

3y+2y=2x\\ \\5y=2x\\ \\y=\dfrac{2}{5}x

Now,

AD=3y\\ \\DC=DB+BC=2y+x=2y+\dfrac{2}{5}y=\dfrac{12}{5}y

So,

AD:DC=3y:\dfrac{12}{5}y=15:12=5:4

6 0
3 years ago
Read 2 more answers
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makkiz [27]
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3 0
2 years ago
I need help plz!!!!!!
GrogVix [38]

Answer:

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Step-by-step explanation:

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3 years ago
The quotient of m and 7
xxTIMURxx [149]

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2 years ago
Solve - 3/5 x + 1/5 > 7/20
shusha [124]

Answer:

x< -1/4

Step-by-step explanation:

- 3/5 x + 1/5 > 7/20

Subtract 1/5 from each side

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-3/5x > 7/20 -1/5

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x < -1/4

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3 years ago
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