Answer:
A^(2) + B^(2) = C^(2)?????????????
Step-by-step explanation:
that's an isosceles triangle, not a right-angle triangle
The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
$268.00 base price
8% is $21.44
Total with tax $289.44
Answer:its c
Step-by-step explanation:
that is how i would do it.