Solve for x x^2 + 6x + 1 = 0
1 answer:
You might be interested in
Answer:
This case has NO solutions.
Step-by-step explanation:
Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.
This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":
As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).
Therefore, there is no angle we can find to build a triangle with the given data.
Answer:
x= 0 , ,
Step-by-step explanation:
Given, equation is +
=
. →→→ (1)
Now, by cubing the equation on both sides, we get
( +
)³ = (
)³
⇒ (15x-1) + (13x+1) + 3××
(
+
) = 64 x.
⇒ 28x + 3××
(
) = 64x.
(since from (1), +
=
)
⇒ 12× ×
(
)= 36x.
⇒ 3x = .
Now, once again cubing on both sides, we get
(3x)³ = ()³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x = ; x =
therefore, solution is x= 0 , ,