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den301095 [7]
4 years ago
6

Which of the following chemical formulas shows a covalent compound? A.CO2 B.MgO C. NaCl D.HBr

Chemistry
2 answers:
Nikitich [7]4 years ago
7 0
A I have had that question
gogolik [260]4 years ago
5 0
A...because both of them(carbon and oxygen)are nonmetal
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Convert 5,500 mg to kg. Show your work to receive full credit.
Ivanshal [37]
5500 mg = 0.0055 kg. is the answer
7 0
3 years ago
WILL GIVE BRAINLIEST!!!
Rus_ich [418]

Answer:

The answer is B

Explanation:

The answer is B because representative particles can only be atoms.

3 0
3 years ago
A sudstance particle with no charge
Dafna11 [192]

Answer:

Neutron

Explanation:

Neutron, neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen. It has no electric charge and a rest mass equal to 1.67493 × 10−27 kg—marginally greater than that of the proton but nearly 1,839 times greater than that of the electron.

4 0
3 years ago
Y-Chart<br> Explain how an invasive species can influence each aspect of an ecosystem.
Katen [24]

Answer:

Invasive species are an organism that causes ecological or economic harm in a new environment where it's not native.

Explanation:

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Invasive species is capable of causing extinctions to native plants and animals, reducing biodiversity, competing with native organisms for limited resources, and altering habitats. This can also result a huge economic impacts and fundamental disruptions of coastal and the great lakes of the ecosystems.

I hope it helps you.

6 0
4 years ago
Concentrated nitric acid is 15.6M and has a density of 1.41g/mL. What is the weight percent of concentrated HNO3?
tankabanditka [31]
Molarity= mol/ liters

since the molarity is given, we can assume that we have 1.0 Liters of solution

15.6 M= mol/ 1 liters---> this means that we have 15.6 moles of HNO3

we need to convert these moles to grams using the molar mass of HNO3

molar mass  HNO3= 1.01 + 14.0 + (3 X 16.0)= 63.01 g/mol

15.6 mol HNO3 (63.01 g/ mol)= 983 grams HNO3

now we have to determine the grams of solution using the assumption of 1 liters of solution and the density

1 liters= 1000 mL

1000 mL (1.41 g/ ml)= 1410 grams solution

mass percent= mass of solute/ mass of solution x 100

mass percent= 63.01/ 1410 x 100= 4.47 %
6 0
4 years ago
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