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Zolol [24]
3 years ago
11

A substance might freeze when thermal energy is ______ the substance.

Chemistry
2 answers:
inessss [21]3 years ago
7 0

Answer:

the answer is when the thermal energy is removed from the substance.

maxonik [38]3 years ago
6 0
I think it’s “Removed from”
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The ph of lemon juice is approximately 2.4. at this ph, the hydronium ion concentration is closest to which value? 1. 250 m 2. 4
babymother [125]

Answer is: concentration of hydrogen cations in lemon juice is 4.00 × 10−3 m.

pH = 2.4.

pH = -log[H₃O+].

[H₃O+] = 10∧(-pH).

[H₃O+] = 10∧(-2.4).

[H₃O+] = 0.004 mol/L.

pH value (potential of hydrogen - [H+]) is a logarithmic scale that specify the acidity or basicity of an aqueous solution. When pH is greater than seven, aqueous solution is basic, below seven is acidic and when pH is equal seven, solution is neutral.
8 0
3 years ago
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Which of the following adaptations would you expect tofind in an animal in the alpine biome, but not in the taiga
almond37 [142]
I think the best answer is migration. In an alpine biome, animals have two problems which is the very cold temperature and the UV rays from the sun. Most alpine animals hibernate and migrate to warmer areas of the mountains when the temperature continues to drop.
7 0
4 years ago
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What is the term for secondary consumers in an ecosystem?
borishaifa [10]
Answer: Carnivores, or Meat Eaters

Reason/Explanation:
Another name for Secondary Consumers is Carnivores. They eat flesh, and meat. They feed on the herbivores. An example of this is snakes, squirrels, ravens, etc. They eat plants and meat.


-DustinBR
7 0
4 years ago
Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
5 0
3 years ago
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Part i. you considered the equilibrium: fe3+(aq) + scn-(aq) fe(scn)2+(aq), and compared the color of the solutions in four test
Alexus [3.1K]

Answer:

The equilibrium will be shifted to lift with the formation of a brown gelatinous precipitate of Fe(OH)₃.

Explanation:

  • Le Chatelier's principle states that <em>"when any system at equilibrium for is subjected to change in concentration, temperature, volume, or pressure, then the system readjusts itself to counteract the effect of the applied change and a new equilibrium is established that is different from the old equilibrium"</em>.
  • The addition of NaOH will result in the formation of Fe(OH)₃ precipitate which has a brown gelatinous precipitate.
  • The formation of this precipitate cause removal and decrease of Fe³⁺ ions.
  • According to Le Chatelier's principle, the system will be shifted to lift to increase Fe³⁺ concentration and reduce the stress of Fe³⁺ removal and readjust the equilibrium again. So, the [Fe(SCN)²⁺] decreases.
  • Increasing [Fe³⁺] will produce a yellow color solution that contains a brown gelatinous precipitate of Fe(OH)₃.
3 0
3 years ago
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