Question

What uniform magnetic field, applied perpendicular to a beam

Answer 1

Answer:

The magnetic field is $2.11\times10^{-5}\ T$

Explanation:

Given that,

Speed $v=1.30\times10^{6}\ m/s$

Radius = 0.350 m

We need to calculate the magnetic field

Using formula of magnetic field

$B =\dfrac{mv}{qr}$

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

$B=\dfrac{9.1\times10^{-31}\times1.30\times10^{6}}{1.6\times10^{-19}\times0.350}$

$B=2.11\times10^{-5}\ T$

Hence, The magnetic field is $2.11\times10^{-5}\ T$