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Minchanka [31]
4 years ago
9

What uniform magnetic field, applied perpendicular to a beam

Physics
1 answer:
schepotkina [342]4 years ago
5 0

Answer:

The magnetic field is 2.11\times10^{-5}\ T

Explanation:

Given that,

Speed v=1.30\times10^{6}\ m/s

Radius = 0.350 m

We need to calculate the magnetic field

Using formula of magnetic field

B =\dfrac{mv}{qr}

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

B=\dfrac{9.1\times10^{-31}\times1.30\times10^{6}}{1.6\times10^{-19}\times0.350}

B=2.11\times10^{-5}\ T

Hence, The magnetic field is 2.11\times10^{-5}\ T

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