Answer:
500 J
Explanation:
In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:
25 N * 20 m = 500 J
Answer:
Explanation:
For elastic collision , the formula for velocity of .06 kg is
v₁ = (m₁-m₂)/(m₁+m₂) u₁ + 2m₁m₂/(m₁+m₂) u₂
=( .06-.09 / .06+.09 ) 5.5 + (2 x .06 x .09 / .06+.09 ) 3.4
=( -.03 / .15) x 5.5 + (2 x .0054 / .15) x 3.4
= -1.1 +.2448
= - 0 .8552 m/s
Its direction will be - opposite direction
the formula for velocity of .09kg is
v₂ = (m₂-m₁)/(m₁+m₂) u₂ + 2m₁m₂/(m₁+m₂) u₁
= ( .09-.06 / .06+.09 ) 3.4 + (2 x .06 x .09 / .06+.09 ) 5.5
= .68 +.396
= 1.076 m / s
Its direction will be in the same direction .
If you're willing to consider fractions or decimals,
then there are an infinite number of answers.
Like (2.5 x 160), and (15 x 26-2/3).
If you want to stick to only whole numbers,
then these 8 combinations do:
1, 400
2, 200
4, 100
5, 80
8, 50
10, 40
16, 25
20, 20
Answer:
answer is DE I hope it will help you please follow me
