Answer:
Acceleration, ![a=-1.5\ m/s^2](https://tex.z-dn.net/?f=a%3D-1.5%5C%20m%2Fs%5E2)
Explanation:
It is given that,
Initial velocity of the car, u = 10 m/s (in right)
Final velocity of the car, v = -5 m/s (in left)
Time taken, t = 10 s
Let a is the acceleration of the car. It can be calculated using the equation of kinematics. The equation is as :
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
![a=\dfrac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D)
![a=-1.5\ m/s^2](https://tex.z-dn.net/?f=a%3D-1.5%5C%20m%2Fs%5E2)
So, the acceleration of the car is
. Hence, this is the required solution.
Answer:
The moon's gravity pulls the Earth to make tides.
Explanation:
The Moons Gravity Pulls On The Earth With Different Strenght Making High Tide And Low Tide.
Hope This Helps!
The answer is Alternating Current
Answer:
6.5 x 10^32 eV
Explanation:
mass of particle, mo = 1 g = 0.001 kg
velocity of particle, v = half of velocity of light = c / 2
c = 3 x 10^8 m/s
Energy associated to the particle
E = γ mo c^2
![E=\frac{m_{0}c^}2}{\sqrt{1-\frac{v^{2}}{c^{2}}}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bm_%7B0%7Dc%5E%7D2%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E%7B2%7D%7D%7Bc%5E%7B2%7D%7D%7D%7D)
![E=\frac{m_{0}c^}2}{\sqrt{1-\frac{c^{2}}{4c^{2}}}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bm_%7B0%7Dc%5E%7D2%7D%7B%5Csqrt%7B1-%5Cfrac%7Bc%5E%7B2%7D%7D%7B4c%5E%7B2%7D%7D%7D%7D)
![E=\frac{2m_{0}c^}2}{\sqrt{3}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B2m_%7B0%7Dc%5E%7D2%7D%7B%5Csqrt%7B3%7D%7D)
![E=\frac{2\times0.001\times9\times10^{16}}{1.732}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B2%5Ctimes0.001%5Ctimes9%5Ctimes10%5E%7B16%7D%7D%7B1.732%7D)
![E=1.04\times10^{14}J](https://tex.z-dn.net/?f=E%3D1.04%5Ctimes10%5E%7B14%7DJ)
Convert Joule into eV
1 eV = 1.6 x 10^-19 J
So, ![E=\frac{1.04\times10^{14}}{1.6\times10^{-19}}=6.5\times10^{32}eV](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1.04%5Ctimes10%5E%7B14%7D%7D%7B1.6%5Ctimes10%5E%7B-19%7D%7D%3D6.5%5Ctimes10%5E%7B32%7DeV)
The valence electrons are the one furthest from the nucleus