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AlexFokin [52]
3 years ago
11

Find the lateral area of the square pyramid shown to the nearest whole number.

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

4,300

Step-by-step explanation:

Lateral area of a squared Pyramid is given as ½ × Perimeter of base (P) × slant height of pyramid

Thus, we are given,

Side base length (s) = 43 yd

height (h) = 25 yd

Let's find the perimeter

Permimeter = 4(s) = 4(43) = 172 yd

Calculate the slant height using Pythagorean theorem.

Thus, l² = s²+h²

l² = 43²+25² = 1,849+625

l² = 2,474

l = √2,474

l ≈ 50 yd

=>Lateral area = ½ × 172 × 50

= 172 × 25

= 4,300 yd

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On a map, 1 inch equals 5.2 miles. Two house are 3.5 inches apart on the map. What is the actual distance between the house?
MissTica

Answer:

18.2 miles

Step-by-step explanation:

simple multiplication:

We know that 1 inch of distance on the map is equal to 5.2 miles.

Using this knowledge we can multiply the amount of inches by the miles per inch.

5.2*3.5=18.2 miles apart

Hope this helps!!

4 0
3 years ago
If it is 10:46 am how many minutes until noon?
valentinak56 [21]
Since there's 1 hour and 14 minutes until noon, and one hour is 60 minutes, 60 + 14 = 74 minutes until noon.
7 0
3 years ago
Read 2 more answers
[[ 20 POINTS IF YOU ANSWER THIS QUESTION CORRECTLY. ]]
dezoksy [38]

Answer: the height of the kite is 106.065 ft

Step-by-step explanation:

The length of the kite represents the hypotenuse of the right angle triangle. The height of the kite represents the opposite side of the right angle triangle.

To determine x, the height of the kite, we would apply the sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse

Therefore,

Sin 45 = x/150

Cross multiplying, it becomes

x = 150Sin45 = 150 × 0.7071

x = 106.065 ft

3 0
3 years ago
Find the value of x. Round to the nearest tenth of a foot.
Reptile [31]

Answer:

17

Step-by-step explanation:

7 0
4 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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