What is 3.6 converted to a fraction?

Estimate the area for the figure below. Assume that each square in the grid is one square inch.

Nutka1998 [239]

we will segment the sqaure in the shape into the following

full square,

0.75

0.5

0.25

full square = 68

0.75 = 18 x 0.75 = 13.5

0.5 = 5 x 0.5 = 2.5

0.25 = 17 x 0.25 = 4.25

to get the area of figure, we will add up the values that we have gotten

so,

Area of the figure = 68 + 13.5 + 2.5 + 4.25

Area of the figure = 88.25 square meter

5 0

1 year ago

Nikhil gets paid a 5 percent commission on every pair of shoes that he sells. He earned $1.00 on the last pair of shoes that he

Pepsi [2]

Answer: The answer is C. $20.00

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago

An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can

serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0 ......[1]

the solution for the equation is given by:

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

$t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}$

$t= \frac{-80\pm \sqrt{6400+19200}}{-32}$

$t= \frac{-80\pm \sqrt{25600}}{-32}$

Simplify:

$t = -\frac{5}{2}$ = -2.5 sec and $t = \frac{15}{2}$ = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0

3 years ago

(9) power 3 +(3) power 2+(6) power 3+(15)power 2=?

Kisachek [45]

Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!

So-------

9^3=729

3^2=9

6^3=216

15^2=225

Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.

Therefore, your final answer will be 1,174.

If you have any questions on this, I'm happy to help you. :)

5 0

3 years ago