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Deffense [45]
3 years ago
9

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find x

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

x = 1

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, thus

AE = CE , substitute values

11x - 3 = 12 - 4x ( add 4x to both sides )

15x - 3 = 12 ( add 3 to both sides )

15x = 15 ( divide both sides by 15 )

x = 1

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Arisa [49]

Answer:

there is no value its letter

Step-by-step explanation:

there is no value to a letter duh


3 0
3 years ago
Paulo has $145 in his savings account. He earns $36 a week moving lawns. If Paulo saves all of his earnings, after how Many week
kondor19780726 [428]

Answer:

433-145=288

288/36=8

answer=8

Step-by-step explanation:


6 0
3 years ago
Identify the domain and range of y = 4x - 5 + 3
Zepler [3.9K]

Answer:

\huge\boxed{\text{Domain:}\ D=\mathbb{R}=(-\infty;\ \infty)}\\\boxed{\text{Range:}\ R=\mathbb{R}=(-\infty;\ \infty)}

Step-by-step explanation:

y = 4x - 5 + 3 = 4x - 2

It's an equation of a line in the slope-intercept form.

y = 4x - 2 → f(x) = 4x - 2 - it's a lienar function.

The domain of a linear function is the set of all real numbers.

If a slope of linear function is different than 0, then the range is the set of all real numbers.

5 0
3 years ago
X^3 -x-340<br><br>please explain how you got it <br><br>please help me​
Makovka662 [10]

Answer: x = 18.439

Step-by-step explanation:

x³-x = 340

x² = 340

x = √340 = 18.439

8 0
3 years ago
In a baseball tournament, teams get 5 points for a win, 3 points for a tie and 1 point for a loss Nathan’s team has 29 points ho
puteri [66]

Answer:

37 different combinations

Step-by-step explanation:

First of all, we will count the possible combinations that add up to 29.

-Losses only;

One possibility: 29 losses

-Ties & losses;

Nine possibilities: 1 tie and 26 losses; 2 ties and 23 losses; 3 ties and 20 losses;4 ties and 17 losses; 5 ties and 14 losses; 6 ties and 11 losses; 7 ties and 8 losses; 8 ties and 5 losses; 9 ties and 2 losses

-Wins & losses

Five possibilities: 1 win and 24 losses; 2 wins and 19 losses; 3 wins and 14 losses; 4 wins and 9 losses; 5 wins and 4 losses

Now, what we want to find from the question is number of possibilities for wins, ties, and losses all together. So, we will count up the ties and losses in the remainder for each case of a given number of wins.

Thus;

For 0 Wins: 0 ties and 29 losses; 1 tie and 26 losses; 2 ties and 23 losses; 3 ties and 20 losses;4 ties and 17 losses; 5 ties and 14 losses; 6 ties and 11 losses; 7 ties and 8 losses; 8 ties and 5 losses; 9 ties and 2 losses.

Which sums up to 10 possibilities

For 1 win; 0 ties and 24 losses; 1 tie and 21 losses........8 ties and 0 losses.

Which sums up to 9 possibilities

For 2 wins; 0 ties and 19 losses; 1 tie & 16 losses............ 6 ties and 1 loss.

Which sums up to 7 possibilities

For 3 wins; 0 ties and 14 losses; 1 tie and 11 losses ....... 4 ties and 2 losses.

Which sums up to 5 possibilities

For 4 wins; 0 ties & 9 losses; 1 tie and 6 losses....... 3 ties and 0 losses

Which sums up to 4 possibilities

For 5 wins; 0 ties and 4 losses; 1 tie and 1 loss

Which sums up to 2 possibilities

Thus;

Total number of possibilities of combinations of wins, ties and losses = 10 + 9 + 7 + 5 + 4 + 2 = 37

8 0
3 years ago
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