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Anarel [89]
3 years ago
7

Chelsey wants to join a fitness club. The fitness club charges an initial membership fee of $55 and a monthly fee of $19.50. She

has $250 to spend. Write and solve an equation to find the number of months she can be a member.
Mathematics
1 answer:
Kay [80]3 years ago
4 0
So if you have to pay 55 out front and then continue to pay 19.50 monthly the equation will look like this:
19.50*m + 55 = x
(M stands for month)
She has 250 dollars to spend so add that in for x
<span>19.50*m + 55 = 250. 
Use inverse operations.
250-55 and 55-55
19.50*m = 195
195/19.50 and 19.50/19,50
m=10
Your answer is 10</span>
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Artemon [7]

Answer:

The m∠YXW is 125°.

Addition equation: m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

Step-by-step explanation:

To find the m∠YXW you would need to add the m∠YXZ and m∠ZXW together:

m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

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3 years ago
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ElenaW [278]
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If p is inversely proportional to the square of q, and p is 18 when q is
aniked [119]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Angle D=(7b+1) angle E=(2b+1) and angle F=(b+8) what is the measure of angle E
Mademuasel [1]

angleD=(7b+1)angle E=(2b+1)and angle F=(b+8)

3 0
3 years ago
Read 2 more answers
A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter
Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

x+y=15\operatorname{cm}

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}

We can now refine the equation as follow;

\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}

ANSWER:

The length of the shorter piece of wire is 6cm

7 0
1 year ago
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