Answer:
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Step-by-step explanation:
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Answer:
Perimeter: 119.11 units length
Step-by-step explanation:
Assuming that EC is the length of one side of the square and one of the legs (l) of the isosceles right triangle, then the hypotenuse (h) of the right triangle is:
h² = 2*l²
h = √(2*22²)
h = 22√2 units length
The perimeter of the figure is the addition of 3 sides of the square, one leg of the triangle and the hypotenuse of the triangle, that is: 4*22 + 22√2 = 22*(4 + √2) ≈ 119.11 units length
Answer:
True
Step-by-step explanation:
As C is the mid-point of BD.
Therefore, BC=DC ...(i)
As AB ⊥ BD and ED ⊥ BD
So, ∠ABC= 90° and ∠EDC= 90°
Therefore, ∠ABC=∠EDC= 90° ...(ii)
As two line segments, AE and BD intersect at point C, so the vertically opposite angles are equal.
Therefore, ∠BCA=∠DCE ...(iii)
Now, in ΔABC and ΔEDC,
Angle, ∠BCA=∠DCE [ from equation (iii)]
Side, BC=DC [ from equation (i)]
Angle, ∠ABC=∠EDC [ from equation (ii)]
So, by ASA property of congruency, ΔABC and ΔEDC are congruent
Hence, ΔABC ≅ ΔEDC.