<h3>
Answer: x = 6</h3>
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Work Shown:
![\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\](https://tex.z-dn.net/?f=%5Clog_%7B4%7D%28x%2B10%29%2B%5Clog_%7B4%7D%28x-2%29%3D%5Clog_%7B4%7D%2864%29%5C%5C%5C%5C%5Clog_%7B4%7D%5Cleft%28%28x%2B10%29%28x-2%29%5Cright%29%3D%5Clog_%7B4%7D%2864%29%5C%5C%5C%5C%28x%2B10%29%28x-2%29%3D64%5C%5C%5C%5Cx%5E2-2x%2B10x-20%3D64%5C%5C%5C%5Cx%5E2-2x%2B10x-20-64%3D0%5C%5C%5C%5C)
![x^2+8x-84=0\\\\(x+14)(x-6)=0\\\\x+14=0 \ \text{ or } \ x-6=0\\\\x=-14 \ \text{ or } \ x=6\\\\](https://tex.z-dn.net/?f=x%5E2%2B8x-84%3D0%5C%5C%5C%5C%28x%2B14%29%28x-6%29%3D0%5C%5C%5C%5Cx%2B14%3D0%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20x-6%3D0%5C%5C%5C%5Cx%3D-14%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20x%3D6%5C%5C%5C%5C)
Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out
x = 6 works as a solution however
1. B 2. A i’m pretty sure they are right
Answer:
D
Step-by-step explanation:
Its d because in the graph the line where they are at is positive and the answer shows (2,2) in the graph.
We can re-group them to add more easily.
300 + 400 = 700
42 + 16 = 58
700+58 = 758
Answer: 758