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Advocard [28]
3 years ago
7

Solve the system of equations: y=2x-3 y=x2-3

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Answer: x = 0 or x = 2

Step-by-step explanation:

To solve this, we must note that the two equations speaks of a single function of y. So

y = 2x - 3 = x² - 3

So from.here we can equate the two together and solve for x.

x² - 3 = 2x - 3, biw convert to a quadratic expression

x² - 2x - 3 + 3 = 0

x² - 2x = 0

Now factorize

x( x - 2 ) = 0, so solving for x

x = 0 or x = 2. .I believed getting the 2 won't be a problem

When x - 2 = 0

Then x = 2.

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Which is the correct calculation of the y-coordinate of point A? 0 (0 - 0)2 + (1 - y2 = 2 O (0 - 1)² + (0- y2 = 22 (0-0)² + (1 -
dimaraw [331]

Answer:

The y-coordinate of point A is \sqrt{3}.  

Step-by-step explanation:

The equation of the circle is represented by the following expression:

(x-h)^{2}+(y-k)^{2} = r^{2} (1)

Where:

x - Independent variable.

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y = \sqrt{3}

The y-coordinate of point A is \sqrt{3}.  

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xz_007 [3.2K]

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Answer:

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Step-by-step explanation:

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