<u>Answer:</u> The standard EMF of the cell is 1.11 V
<u>Explanation:</u>
For the given chemical equation:

The half reaction follows:
<u>Oxidation half reaction:</u>
( × 3)
<u>Reduction half reaction:</u> 
To calculate the
of the reaction, we use the equation:

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Calculating the
using above equation, we get:

Hence, the standard EMF of the cell is 1.11 V
Well protists quite very as organisms i.e it is hard to say if an organism is a protist. Some main features of protists are that they have
1. A membrane enclosed nucleus
2.They are mainly single celled
Also protista are found mainly anywhere water is present for example damp soil, pools and lakes.
Hope this helps :).
In order to find the answer, use an ICE chart:
Ca(IO3)2...Ca2+......IO3-
<span>some.......0..........0 </span>
<span>less.......+x......+2x </span>
<span>less........x.........2x
</span>
<span>Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³
</span>
K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
<span>x = molar solubility = 5.6 x 10</span>⁻³ M
The answer is 5.6 x 10 ^ 3 M. (molar solubility)
Answer:
40/18AR
Explanation:
sorry my answer was late but i hope this helps someone else! I got it right on the test
Question:
how many significant figures are in the measurement 0.0056 ke?
a. four
b. two
c. five
d. three
answer:
b. two