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shepuryov [24]
3 years ago
11

Source of most water that eva6from earth's surface

Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Ocean

Explanation:

The source of most water that evaporates from the earth's surface is the ocean.

The world's oceans covers about 71% of the total land area of the world.

It is logical enough to have the largest water body on earth as the place where most evaporation is taking place.

Evaporation is in important process in the hydrologic cycle where water is turned to vapor.

learn more:

Phase change brainly.com/question/1875234

#learnwithBrainly

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What is the difference between a compound and mixture
Flauer [41]
Here is what i got from my notes, hope this helps.

Mixture components keep their identities.
Mixture components CAN be separated PHYSICALLY
Homogenous Mixture: You CAN NOT the different parts (phases) of the mixture
Heterogeneous Mixture : You CAN SEE the different parts (phases) of the mixture easily
A solution is a HOMOGENOUS MIXTURE of particles so small that they cannot be seen and CANNOT be filtered out
A compound is something that is made from something that can be separated from 2 things.
It is a mixture and has chemical bonds.
5 0
4 years ago
At the _______ point of a substance, the particles have enough kinetic energy to break free from their fixed positions.
Natasha_Volkova [10]

Answer:

At the nucleus point of a substance, the particles have enough kinetic energy to break free from their fixed positions.

Answer : nucleus

5 0
2 years ago
Compounds X has the formula C7H15Cl; Y is C7H15Br. X undergoes base-promoted E2 elimination to give a single alkene product Z. Y
djverab [1.8K]

Answer:

See explanation and image attached

Explanation:

Let us examine the statements in the question carefully. First of all, we will discover that the products of the E2 elimination of the both compounds are isomeric. However Y does not undergo SN2 reaction as  X does.

The fact that SN2 reaction does not occur in Y confirms that the bromine atom is attached to a tertiary carbon atom and SN2 reaction does not occur due to steric hinderance. Since X undergoes SN2 reaction in aprotic solvent, the chlorine atom must be attached to a secondary carbon atom.

However, E2 reactions does occur with tertiary alkyl halides when strong bases such as OH^- or RO^- are used.

The question also stated that the catalytic hydrogenation of Z affords 3-ethylpentane.

Putting all these together, the structures of X and Y have been suggested in the image attached to this answer.

3 0
3 years ago
1. An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 4.50 L of oxygen gas was rele
Musya8 [376]

Answer:

1. 59.1 g HgO

2. A.) 38.2 L

3. B.) It is directly proportional to the number of moles of the gas.

Step-by-step explanation:

1. Mass of HgO

We know we will need a chemical equation with masses and molar masses, so let's gather all the information in one place.

M_r:   216.59

          2HgO ⟶ 2Hg + O₂

(a) Calculate the <em>moles of O₂</em>  

pV = nRT            Divide each side by RT  

 n = (pV)/(RT)  

<em>Data: </em>

p = 0.970 atm  

V = 4.50 L  

R = 0.082 06 L·atm·K⁻¹mol⁻¹  

T = 390.0 K  

<em>Calculation: </em>

n = (0.970 × 4.500)/(0.082 06 × 390.0)  

n = 0.1364 mol O₂

(b) Calculate the <em>moles of HgO </em>

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

(c) Calculate the <em>mass of HgO </em>

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = <em>59.1 g HgO</em>

This isn't any of the options in your list. Have I made an error?

2. Volume of Hydrogen

              Mg + 2HCl ⟶ MgCl₂ + H₂

n/mol:              3.00

(a) Calculate the <em>moles of H₂ </em>

The molar ratio is (1 mol H₂/2 mol HCl).

Moles of H₂ = 3.00 mol HCl × (1 mol H₂/2 mol HCl)

Moles of H₂ = 1.50 mol HCl

(b) Calculate the <em>volume of H₂ </em>

pV = nRT     Divide both sides by p

 V = (nRT)/p

<em>Data: </em>

n = 1.50 mol

T = 298 K

p = 0.960 atm

<em>Calculation: </em>

V = (1.5 × 0.082 06 × 298)/0.960

V = 38.2 L

3. Volume of gas

pV = nRT

 V = nRT/p

If T and p are constant, (RT)/p = constant = k

V = kn

V ∝ n

The volume is directly proportional to the number of moles of the gas.

3 0
4 years ago
A protein was previously determined to contain 15.7 wt% nitrogen. A 647 m aliquot of a solution containing the protein was diges
Ket [755]

Answer:

431.38 mg protein / mL

Explanation:

This is an example of the <em>Kjeldahl method</em>, for nitrogen determination. All nitrogen atoms in the protein were converted to NH₃ which then reacted with a <u>known excess of HCl</u>. This excess was later quantified via titration with NaOH.

First we calculate the <u>total amount of H⁺ moles from HCl</u>:

  • 0.0388 M HCl * 10.00 mL = 0.388 mmol H⁺

Now we calculate the <u>excess moles of H⁺</u> (the moles that didn't react with NH₃ from the protein), from the <u>titration with NaOH</u>:

  • HCl + NaOH → H₂O + Na⁺ + Cl⁻
  • 0.0196 M * 3.83 mL = 0.075068 mmol OH⁻ = 0.0751 mmol H⁺

Now we substract the moles of H⁺ that reacted with NaOH, from the total number of moles, and the result is the <u>moles of H⁺ that reacted with NH₃ from the protein</u>:

  • HCl + NH₃ → NH₄⁺ + Cl⁻
  • 0.388 mmol H⁺ - 0.0751 mmol H⁺ = 0.313 mmol H⁺ = 0.313 mmol NH₃

With the moles of NH₃ we know the moles of N, then we can <u>calculate the mass of N</u> present in the aliquot:

  • 0.313 mmol NH₃ = 0.313 mmol N
  • 0.313 mmol N * 14 mg/mmol = 4.382 mg N

From the exercise we're given the concentration of N in the protein, so now we <u>calculate the mass of protein</u>:

  • 4.382 mg * 100/15.7 = 27.91 mg protein

Finally we <u>calculate the protein concentration in mg/m</u>L, <em>assuming your question is in 647 μL</em>, we first convert that value into mL:

  • 647 μL * \frac{1L}{10^{6}uL} *\frac{1000mL}{1L} = 0.647 mL
  • 27.91 mg / 0.647 mL = 431.38 mg/mL
3 0
3 years ago
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