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Shalnov [3]
3 years ago
11

Pls answer I’ll give you brainly

Mathematics
1 answer:
Anna71 [15]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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Find the standard form of the equation of each circle with the endpoints of a diameter (1,8) and (-3,2)
eimsori [14]

Answer:

(x+1)^2+(y-5)^2=13

Step-by-step explanation:

3 0
3 years ago
Y I have<br>£ 1. I spend 45p. How much do I have left?​
loris [4]

Answer:

55p

Step-by-step explanation:

£1 (100p) - 45p = 55p

3 0
3 years ago
If a gambler rolls two dice and gets the sum of 7, he wins $20. If he gets a sum of 4, he wins $40. The cost of playing is $14.
Rufina [12.5K]
The expectation is that he should be losing money because the chances he rolls either a 7 or a 4 out of 2 dice (which is 1-12) is 1/6. I think this is what you're trying to ask I hope I helped
5 0
4 years ago
Read 2 more answers
Ejercicio 3. Aplica las leyes de los exponentes de potencia elevada a otra potencia y de producto,
OLga [1]

Los resultados son los siguientes:

  1. 2097152
  2. \frac{1}{729}
  3. b^{12}
  4. x^{24}
  5. x^{\frac{6}{5} }
  6. 3600
  7. a^{6}\cdot b^{10}\cdot c^{-8}
  8. 200\cdot x^{19}
  9. 108\cdot y^{6}

En este ejercicio debemos aplicar cualesquiera de las siguientes propiedades asociadas a los exponentes:

(i) (a^{b})^{c} = a^{b\cdot c}

(ii) a^{c}\cdot b^{c} = (a\cdot b)^{c}

(iii) a^{-b} = \frac{1}{a^{b}}

(iv) a^{b} = a^{b}, donde a es negativo o positivo y b es par.

(v) (-a)^{b} = -a^{b}, donde a es positivo y b es impar.

(vi) a^{b}\cdot a^{c} = a^{b+c}

A continuación, tenemos los siguientes resultados:

a) (2^{3})^{7} = 8^{7} = 2097152

b) (3^{3})^{-2} = 3^{-6} = \frac{1}{729}

c) (b^{3})^{4}=b^{12}

d) [(x^{2})^{3}]^{4} = (x^{6})^{4} = x^{24}

e) \left(x^{\frac{3}{5} }\right)^{2} = x^{\frac{6}{5} }

f) (3\cdot 4\cdot 2)^{5} = 3^{2}\cdot 4^{2}\cdot 5^{2} = 9\cdot 16\cdot 25 = 3600

g) (a^{3}\cdot b^{5}\cdot c^{-4})^{2} = (a^{3})^{2}\cdot (b^{5})^{2}\cdot (c^{-4})^{2} = a^{6}\cdot b^{10}\cdot c^{-8}

h) (2\cdot x^{5})^{3}\cdot (-5\cdot x^{2})^{2} = (2^{3}\cdot x^{15})\cdot [(-5)^{2}\cdot x^{4}] = (8\cdot x^{15})\cdot (25\cdot x^{4}) = (8\cdot 25)\cdot x^{19} = 200\cdot x^{19}

i) \left(3\cdot y^{\frac{2}{3} }\right)^{3}\cdot (2\cdot y^{2})^{2} = (27\cdot y^{2})\cdot (4\cdot y^{4}) = 108\cdot y^{6}

Invitamos cordialmente a consultar esta pregunta sobre potencias: brainly.com/question/24239709

8 0
3 years ago
Solve the equations to find if they are either
Lelechka [254]
I hope this helps you




1) inconsistent


2) equivalent


3) inconsistent


4) consistent


5) consistent


6) equivalent

7 0
3 years ago
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