Answer:

Step-by-step explanation:
For standard form the circle's equation we need the centre of the circle and the radius.
Step 1: <em><u>Find the centre</u></em>
If the centre is not given find the end points of the diameter
and then find the mid point.
Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )
The mid-point of the diameter is :

Therefore, centre of the circle = ( -3 , 2 )
Step 2 : <u>Find radius</u>
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Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )
That is ,


Therefore ,

Step 3 : <u>Equation of the circle</u>
Standard equation of the circle with centre ( h ,k )
and radius ,r is :

Therefore, the equation of the circle with centre ( -3, 2)
and radius = 6 is :
