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Andrew [12]
3 years ago
5

Determine which ordered pair makes the equation true. 2x + y = 11

Mathematics
1 answer:
slavikrds [6]3 years ago
4 0
There is no one ordered pair that makes the equation true, this is a line which has infinitely many ordered pairs that are true...

2x+y=11  subtract 2x from both sides and you have the line in slope intercept form..

y=11-2x

For any real given value of x, you will get one real unique corresponding value for y, resulting in infinitely many unique (x,y) values, points, or ordered pairs, satisfying the given equation.

I assume that you were given "choices" to pick from because of the above reality.  So if any of your choices does not satisfy y=11-2x it is not an ordered pair satisfying the equation.
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HELP PLEASE: Which is the equation of the graphed line written in
maksim [4K]

Answer:

x - y = 0

Step-by-step explanation:

Required

The graph equation

From the graph, we have:

(x_1,y_1) = (0,0)

(x_2,y_2) = (1,1)

The slope of the graph is:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{1-0}{1-0}

m = \frac{1}{1}

m =1

So, the graph equation is:

y = m(x - x_1) + y_1

y = 1 * (x - 0) + 0

y = 1 * x

y = x

In standard form, we have:

x - y = 0

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6 0
3 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
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