Answer:
B. Beth's age is 18 years, and Sally's age is 42 years.
Step-by-step explanation:
You can solve this question in a couple of different ways. First, you can use process of elimination. You know that Sally is older than Beth because she has to be 3 times older 6 years ago, so you can get rid of options C and D because they both show Beth as being older. Now you only have A and B, and you can use a different process. Now from just looking at it, you can tell that A actually already shows Sally as 3 times Beth's age, 15 * 3 = 45. If you go to B, you can go ahead and subtract 6 from 18 (Beth's age) which will give you 12, and then multiply that by 3 to get 36. Now if you take 42 (Sally's age) and subtract 6 from it as well, you will get 36. This means that is lines up. To simplify, you are subtracting 6 from both 18 and 42, and then you are multiplying the lower number by 3 to see if it gets to the bigger number.
Hope this helped ^-^
Answer:
80 minutes or 1 h 20 minutes
Step-by-step explanation:
15-13=2
2/0.025=80
So we can conclude that it takes 80 minutes till it reaches 13 feet.
Factors are the numbers you multiply together to get given number.
All possible factorizations of number 18 by two factors are:
- 18=1·18;
- 18=2·9;
- 18=3·6.
Answer: 1 and 18, 2 and 9, 3 and 6.
Here are two ways of doing it.
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1) The current price is 100% of the price. The price went down by 6%, so since 100% - 6% = 94%, the new price is 94% of the original price.
94% * 175 = 0.94 * 175 = 164.50
The new price is 164.50
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2) The discount is 6% of 175, so first, we find the discount.
6% of 175 = 0.06 * 175 = 10.5
Now we subtract the amount of the discount from the original price.
175 - 10.50 = 164.50
The new price is 164.50
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As you can see, both methods give you the same answer, 164.50
Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
