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stira [4]
3 years ago
11

Find two square numbers which a Have the sum of 130

Mathematics
1 answer:
Bad White [126]3 years ago
8 0
1 + 129 equals 130 that equals 130
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Find a solution of the quadratic equation.6x squared + 7x + 2 =0
worty [1.4K]

Given the equation:

6x^2+7x+2=0

We will use the following rule to find the solution to the equation:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

From the given equation: a = 6, b = 7, c = 2

So,

\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}

So, the answer will be option B) x = -1/2, -2/3

5 0
1 year ago
Name all the factors of 12
N76 [4]

Answer:

1,2,3,4,6,12

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Write 368% as a mixed number.
Allushta [10]

Answer:

3\frac{17}{25}

Step-by-step explanation:

368%

<em>convert to a fraction</em>

\frac{368}{100}

<em>divide top and bottom by 2</em>

<em />\frac{184}{50}<em />

<em>divide top and bottom by 2</em>

<em />\frac{92}{25}<em />

92/25 = 3 remainder 17

3\frac{17}{25}

8 0
3 years ago
16.5 + 4.73 show work on how you got the answer
White raven [17]
16.5+4.73= 21.23 it’s basically regular adding just with decimal
8 0
2 years ago
Need help finding the x, y, and z. please and thank you
Reptile [31]

The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

... 2x +z = -4 . . . . simplified

Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)

...15x +3y -12z +2x -3y +z = 123 -1

...17x -11z = 122 . . . . simplified

Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

... 11(2x +z) +(17x -11z) = 11(-4) +122

...22x +17x = 78 . . . . . . simplify a little bit

... x = 78/39 = 2 . . . . . . divide by 39

From above, we find

... z = -4 -2x = -4 -2·2 = -8

... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1

The solution is (x, y, z) = (2, -1, -8).

_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

4 0
3 years ago
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