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aniked [119]
3 years ago
7

What are the amplitude. Phase shift and midline if f(x) = 2 sin(x+pi)-4

Mathematics
1 answer:
kherson [118]3 years ago
7 0
Find the missing angles using either the triangle sum theorem (a2+b2=c2) or inverse trigonometric ratios
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Help AB and CD are straight lines find z​
chubhunter [2.5K]

Answer: z=16

Step-by-step explanation:

Angles on a straight line add up to 180.

As AB is a straight line we can use that to help us find z.

So you would do 68+85+11=164 (I got the 11 from the angle trapped between like C and F as opposite angles are the same).

Then you would do 180-164=16

So z=16

Hope this helps :)

3 0
3 years ago
A cuboid has a square base.
padilas [110]

The length of one side of the square base is 8.5 centimeters.

<u>Given the following data:</u>

  • Volume of cuboid = 867 cm
  • Height = 12 cm

To find the length of one side of the square base:

Mathematically, the volume of a cuboid is given by the formula:

Volume = Base \; area × Height

Substituting the given values, we have:

867 = Base \; area × 12

Base\;area = \frac{867}{12}

Base area = 72.225 cm^2

Now, we can find the length by using the formula:

Area \;of\;a \;square = length^2

72.25 = length^2

Length = \sqrt{72.25}

<em>Length</em><em> = </em><em>8.5 centimeters</em>.

Therefore, the length of one side of the square base is 8.5 centimeters.

Find more information: brainly.com/question/11037225

8 0
2 years ago
Graph this on a coordinate plane f(x)=2x^2-1
rodikova [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
Solve for x<br>2x+4(2x+7)=3(2x+4)??​
xeze [42]
Answer
It’s x= -4 for sure
7 0
3 years ago
Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show
frez [133]
Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
6 0
3 years ago
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