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deff fn [24]
4 years ago
6

The function f(x) = -(x + 5)(x+1) What is the range of the function?

Mathematics
1 answer:
kvv77 [185]4 years ago
6 0

Answer:

All real numbers less than or equal to 4.

Step-by-step explanation:

Rearrange it to vertex form:

-(x + 5)(x+1)

=  - (x^2 + 6x + 5)

= - [( x + 3)^2 - 9 + 5]

= - (x + 3)*2 + 4

So the vertex is at  f(x) = 4 and its a maximum because the coefficient of x^2 is negative.

So the range is all real numbers less than or equal to 4.

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