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Reptile [31]
3 years ago
7

Coach Johnson need to buy shin guards for junior varsity and varsity basketball players the following package of shin guards are

available at the Athletic store.
10 shin guard for $14.50
15 shin guards for $22.50
Coach Johnson need to buy a 30 Shin guards how much money will he save I purchase 30 shin guard inpackage with the lowest unit price compared to the highest unit price
Mathematics
2 answers:
Pavel [41]3 years ago
8 0
$1.50 is the right answer
Firdavs [7]3 years ago
4 0

Answer:

$1.50

Step-by-step explanation:

To find the best deal, we first want to consider price per unit. To find the price per unit, we divide the price by the number of units. For the 10 shin guard package, our price is 14.50, and we divide that by 10 to get 1.45 . Therefore, our unit price for the package of 10 is $1.45 per shin guard. Similarly, we can find the unit price for the package of 15 to be 22.5/15 = $1.50 per shin guard. As 1.50 is greater than 1.45, the lowest unit price is for the package of 10.

The question is asking for us to compare the prices if we bought 30 of each. For the package of 10, we get 1.45*30 (as we're buying 30 for 1.45) = 43.5 as the total price, and for the package of 15, we get 1.5*30 = 45 as our price. As 15 and 10 are both factors of 30, we don't need to worry about converting it back into packages of 10/15. The difference between buying 30 at the lowest and highest unit price is therefore (45-43.5)=1.5 dollars

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The data below contain the number of defects observed on each of 250 lcd screens.0 1 2 4 5 5 3 4 3 4 4 2 2 1 0 2 1 3 4 1 4 5 1 2
nika2105 [10]

Answer:

0.128 ; 0.872 ; 0.748 ; 0.124 ; 0.252

Step-by-step explanation:

Given the data above ;

The frequency distribution generated for the number of defects observed on each of 250 lcd screens are as follows :

__number of defects___frequency

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____2 _______________38

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A.) . What proportion of the screens have more than 4 defects? Give your answer to three decimal places.

More than 4 defects = (number of 5 defects + 6 defects) / total number of defects)

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b. What propotion of the screens have at most 4 defects? Give your answer to three decimal places.

Number of (0 + 1 + 2 + 3 + 4) defects

= (24 + 82 + 38 + 43 + 31) / 250

= 218 / 250 = 0.872

c. What proportion of the screens have fewer than 4 defects? Give your answer to three decimal places.

Number of (0 + 1 + 2 + 3) defects

= (24 + 82 + 38 + 43) / 250

= 187 / 250 = 0.748

d. What proportion of the screens have exactly 4 defects? Give your answer to three decimal places.

Number of 4 defects = 31

= 31 / 250

= 0.124

e. What proportion of the screens have at least 4 defects? Give your answer to three decimal places.

Number of (4 + 5 + 6) defects

= (31 + 26 + 6) / 250

= 63 / 250

= 0.252

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