F(x) = |x + 2| - 3
0 = |x + 2| - 3
0 = x + 2 - 3
0 = x - 1
+ 1 + 1
1 = x
Domain: x > 1 and x < 1
Solution Set of the Domain: {x| 1 > x > 1} and {x|x 1 < x < 1} or (1, 1)
f(x) = |x + 2| - 3
f(x) = |0 + 2| - 3
f(x) = |2| - 3
f(x) = 2 - 3
f(x) = -1
Range: x ≤ 3
Solution Set of the Range: {x|x ≤ 3} or (-∞, 3]
Answer:
answered
Step-by-step explanation:
The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"
<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>
Slope form y2-y1 / x2-x1 = m
20 - 9 = 11
12 - 4 = 9
The slope of the line is 11/9
Pretty sure the answer is F=4 2/3 I think
