The set given by the project grade is {1, 2, 3, 4, 5}. If the random variable, X, is the project grade, the mean of the probability distribution is determined by:
Sum = 1 + 2 + 3 + 4 +5
= 15
Mean of the probability distribution is 15/n, where n = 5
= 15/ 5
= 3
Answer:
see explanation
Step-by-step explanation:
(4)
consider the left side
factor the numerator
cosx - cos³x = cosx(1 - cos²x)
![\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}](https://tex.z-dn.net/?f=%5Cfrac%7Bcosx%281-cos%5E2x%29%7D%7Bsinx%7D%5B%2Ftex%20%3D%20%5Btex%5D%5Cfrac%7Bcosxsin%5E2x%7D%7Bsinx%7D)
cancel sinx on numerator/denominator
= cosxsinx =right side ⇒ verified
(5)
Consider the left side
expand the factors
(1 + cotΘ)² + (1 - cotΘ)²
= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ
= 2 + 2cot²Θ
= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ
= 2cosec²Θ = right side ⇒ verified
(6)
Consider the left side
the denominator simplifies to
cosxtanx = cosx × 
= sinx
= sinx( 
+ 
)
= + 
= tanx + 1 = right side ⇒ verified
If A is your age:
400 - 2A = 244
2A = 400 - 244
2A = 156
A = 78
The vehicle be able to cover the full distance of 340km with on petrol tank if the petrol usage is 14 km/1.
Since the vehicles petrol tank has a capacity of 40 litres and the bvehicles wants to cover a distance of 340 with a pertol usage of 14 km/l.
We need to determine if the petrol in the tank will be enough to cover that distance.
<h3>Distance</h3>
So, distance = petrol usage × volume of tank
Since
- petrol usage = 14 km/l and
- volume of tank = 40 l,
Substituting the values of the variables into the equation, we have
distance = petrol usage × volume of tank
distance = 14 km/l × 40 l
distance = 560 km
Since the distance covered = 560 km which is greater than 340 km, the vehicle will be able to cover the full distance.
So, the vehicle be able to cover the full distance of 340km with on petrol tank if the petrol usage is 14 km/1.
Learn more about distance here:
brainly.com/question/10428039
