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3 years ago

Which expression is NOT equal to 125? (1 point)

1 answer:

3 0

The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"

A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed

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A type of sampling in which individuals to be interviewed are selected based on their proportion or quota in the general populat

Butoxors [25]

A type of sampling in which individuals to be interviewed are selected based on their proportion or quota in the general population being polled is known as public opinion.

What is sampling type of public opinion ?

A survey that measures the entire target population is called a census. A sample refers to a group or section of a population from which information is to be obtained. Survey samples can be broadly divided into two types: probability samples and super samples.

The collective opinion of large segment of the population on an issue, candidate or public policy on which the public may be much divided and lake a consensus.

Learn more about the public opinion is here :

brainly.com/question/28049739

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6 0

2 years ago

LCM of x2+5x+6 and x2-x-6 is ………………………

sergejj [24]

Answer:

$(x^2 - 9)(x + 2)$

Step-by-step explanation:

Given:

$x^2 + 5x + 6$

$x^2 - x - 6$

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

$x^2 + 5x + 6$

$x^2 + 3x + 2x + 6$

$(x^2 + 3x) + (2x + 6)$

$x(x + 3) + 2(x + 3)$

$(x + 2)(x + 3)$

$x^2 - x - 6$

$x^2 - 3x +2x - 6$

$x(x - 3) + 2(x - 3)$

$(x + 2)(x - 3)$

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

$x^2 + 5x + 6 = (x + 2)(x + 3)$

$x^2 - x - 6 = (x + 2)(x - 3)$

The common factors would be: =>

$(x + 2)$ (this is common in both polynomials, so we would take just one of them as a factor.

$(x + 3)$ and,

$(x - 3)$

Their product = $(x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)$

4 0

3 years ago

PLS HURRY and thanks if you answere. A car accelerated from 45 m/S to 0 m/s in 10 seconds what is the average acceleration of th

Eva8 [605]

1: You are looking to find the mps increase over a second

2: 45 m/s from 0 m/s in 10 secs that is 4.5 m/s per second

3: The acceleration is 4.5m/s

4 0

3 years ago

Please help!!!

Nonamiya [84]

Answer:

c. $2a^3x^4-3a^3x^3+a^4x^2$

d. $63x^5y^3-30x^2y^4-7x^3y^2$

Step-by-step explanation:

For this exercise you need to remember the following:

1. The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-$

2. The Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

3. The Distributive property:

$a(b\±c)=ab\±ac$

Knowing that, you can solve the multiplication of the polynomials:

c. $(-2ax^2+3ax-a^2)(-a^2x^2)=\\\\=(-2ax^2)(-a^2x^2)+(3ax)(-a^2x^2)+(-a^2)(-a^2x^2)=2a^3x^4-3a^3x^3+a^4x^2$

d. $(6.3x^3y-3y^2-0.7x)(10x^2y^2)=\\\\=(6.3x^3y)(10x^2y^2)+(-3y^2)(10x^2y^2)+(-0.7x)(10x^2y^2)=63x^5y^3-30x^2y^4-7x^3y^2$

8 0

3 years ago

How do I do this plz help me

USPshnik [31]

Naming the circle is just the only point in the center of the circle (E). The radius is half diameter of the circle so imagine a line connecting the center dot to any dot to the outside. An example of this would be (EC). The diameter is half the circle so any 3 points that cut the circle in half. This could be either (DEC) or (AEB).
So the answers would be:
A: (E)
B: (EC)
C: (DEC)
D: (AEB)

3 0

3 years ago