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3 years ago

Which expression is NOT equal to 125? (1 point)

1 answer:

3 0

The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"

<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>

You might be interested in

Find two different 2 by 2 matrices a and b such that ab=ba

stiv31 [10]

Let $\mathbf A=\mathbf I$ be the identity matrix. Then pick whatever matrix you like for $\mathbf B$ .

8 0

3 years ago

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

Ludmilka [50]

Answer:

$6 \times 10^{7}$

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = $10^{7}$

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = $6 \times 10^{7}$

4 0

3 years ago

The polynomial equation x^6-16x^2=4x^4-64 has complex roots +- 2i . What are the other roots? Use a graphing calculator and a sy

Irina18 [472]

Use u subsitution the solve by grouping
u=x^2
u^3-16u=4u^2-64
u^3-4u^2-16u+64=0
(u^3-4u^2)+(-16u+64)=0
u^2(u-4)+(-16)(u-4)=0
(u^2-16)(u-4)=0
(u-4)(u+4)(u-4)=0
(u+4)(u-4)^2=0

u=x^2
(x^2+4)(x^2-4)^2=0
(x^2+4)((x-2)(x+2))^2=0
(x^2+4)(x-2)²(x+2)²=0
set to zero

x^2+4=0
x^2=-4
x=+/-2i

x-2=0
x=2

x+2=0
x=-2

the other roots are -2 and 2

for graphinc calculator, graph and find x intercepts

3 0

3 years ago

Read 2 more answers

An experiment results in one of the sample points upper e 1e1, upper e 2e2, upper e 3e3, upper e 4e4, or upper e 5e5. comple

ArbitrLikvidat [17]

Given that an experiment results in one of the sample points E1, E2, E3, E4, or E5.

Then P(e1) + P(e2) + P(e3) + P(e4) + P(e5) = 1

If P(E1)=0.1, P(E2)=0.1, P(e4)=0.2, and P(E5)=0.3., then P(E1) = 1 - 0.1 - 0.1 - 0.2 - 0.3 = 0.3

Therefore, P(e3) = 0.3

3 0

3 years ago

Write an equation of the line in point-stope form that passes through the

mash [69]

Answer:

y-8=-4/3(x+2)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-8)/(7-(-2))

m=-12/(7+2)

m=-12/9

simplify

m=-4/3

y-y1=m(x-x1)

y-8=-4/3(x-(-2))

y-8=-4/3(x+2)

4 0

3 years ago