3 years ago

1.Find the area of a circle with the radius of 48mm

Mathematics

1 answer:

OLga [1]3 years ago

3 0

Answer:

hope it helps you see the attachment for further information....

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The gradiant y=2x³-5x+1 at point (2,7)

olga2289 [7]

Given:

The equation of the curve is:

$y=2x^3-5x+1$

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

$y=2x^3-5x+1$

Differentiate the given equation with respect to x.

$y=2(3x^2)-5(1)+(0)$

$y'=6x^2-5$

Now we need to find the value of this derivative at (2,7).

$y'_{(2,7)}=6(2)^2-5$

$y'_{(2,7)}=6(4)-5$

$y'_{(2,7)}=24-5$

$y'_{(2,7)}=19$

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

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Travka [436]

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The new principal after the latest payment is $1,117.60.

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2 years ago

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MA_775_DIABLO [31]

I think the answer
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3 years ago

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Brilliant_brown [7]

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