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liubo4ka [24]
3 years ago
8

I will mark you brainiest if you can answer this

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0
22 touchdowns and 13 field goals
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The sum of 5 consecutive integers is 270
antiseptic1488 [7]
Hello!

This can be written as

(x) + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 270

Add all the values

5x + 1 + 2 + 3 + 4 = 270

Combine like terms

5x + 10 = 270

Subtract 10 from both sides

5x = 260

Divide both sides by 5

x = 52

So the numbers are 52, 53, 54, 55, 56,

Hope this helps!
4 0
3 years ago
Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.
marshall27 [118]

Answer:

\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\  \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right

Step-by-step explanation:

a) \lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}

b) \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}

c) \lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0

d) \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}

e) \lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2

f) \lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}

4 0
3 years ago
Use the line plot below to
Alinara [238K]
1. There were 11 yards mowed. Each yard is represented by an x on the line plot.
2. The most amount of gas used on any one yard was 5/8 of a gallon. The least amount of gas used was 1/8 of a gallon. The difference is (5/8)-(1/8)= (4/8)= 1/2 gallon
7 0
2 years ago
Alice works at a health care facility. She has measured the hemoglobin levels of 200 people. The data follows a normal distribut
rewona [7]
Since the data follows a normal distribution, the 68-95-97 rule can be used to describe the number of people falling under N standard deviations from the mean. Since the standard deviation is 1, hemoglobin levels of 13 -15 g/dL contains 68% of the sample, or 136 people. This means the 32 people have less than 13 g/dL and 32 people have more than 15 g/dL.
5 0
3 years ago
What is an equation for "five more than the product of 7 and a number t?"
fiasKO [112]

the answer is 5+(7t)
6 0
2 years ago
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