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V125BC [204]
3 years ago
14

What are the leading coefficient and degree of the polynomial? 3u+12u'-7u* +1

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

Assuming the given polynomial is

3u + 12 {u}^{2}  - 7 {u}^{3}  + 1

We then rewrite in decreasing powers of u, to get:

- 7 {u}^{3}  + 12 {u}^{2}  + 3u + 1

The leading term is

- 7 {u}^{3}

The leading coefficient is the coefficient of the leading term.

The leading coefficient is -7.

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Ac is tangent to circle o at point c what is the length of ac?
MissTica

Answer:

The Answer is 12

Step-by-step explanation:

Use Pythagorean theorem. AB=8 and BO=5 We still need to find AO

AO=AB+BO

8+5

AO=13

Now solve for AC

AC^2 + OC^2= AO^2

AC^2+5^2=13^2

AC^2+ 25=169

AC^2=144

AC= 12

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3 years ago
7(x – 3) – 5(2x - 4) = 5​
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Answer:

-2

Step-by-step explanation:

7x-21-10x+20=5

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7 0
3 years ago
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What are the dimensions of a rectangular box with a volume of 50b 3 + 75b2 - 2b - 3?
Inessa [10]

Answer:

\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}

Step-by-step explanation:

The formula of a volume of a rectangular box:

V=lwh

<em>l</em><em> - lenght</em>

<em>w</em><em> - width</em>

<em>h</em><em> - height</em>

V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)

Therefore the dinemsions of thisp prism are:

(2b+3)\times(5b-1)\times(5b+1)

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3 years ago
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