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Galina-37 [17]
3 years ago
11

Which statements about moon phases In a lunar month are true?

Chemistry
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

1. The same pattern of phases repeats monthly

2. Waxing moon phases are visible between the new and full moon

6. A full moon appears toward the middle of a lunar month

Explanation:

Moon has eight phases which is used by the ancient people for the identification of date of the month. Phases of moon tells us about the starting, middle and end of the month. At the starting of the month, waxing crescent appears while at the middle of the month, the moon gains its full shape. Phases which occurs between new and full moon is known as waxing.

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A gas in a piston–cylinder assembly undergoes a compression process for which the relation between pressure and volume is given
m_a_m_a [10]

Answer:

1.

A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6

2. W=-8.2kPa

Explanation:

Hello,

1. In this case, for the given p-V equation, one could use the two states to form a 2x2 linear system of equations in terms of A and B:

\left \{ {{0.1^2A+0.1^{-2}B=1} \atop {0.04^2A+0.04^{-2}B=2}} \right.

\left \{ {{0.01A+100B=1} \atop {0.0016A+625B=2}} \right

Whose solution by any method for solving 2x2 linear system of equations (elimination, reduction or substitution) is:

A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6

2. Now, for us to compute the work, we must first compute n, as the power relating the pressure and volume for this process:

P_1V_1^n=P_2V_2^n\\\\\frac{P_1}{P_2}=(\frac{V_2}{V_1}  )^n\\\\\frac{1bar}{2bar}= (\frac{0.04m^3}{0.1m^3}  )^n\\\\0.5=0.4^n\\\\n=\frac{ln(0.5)}{ln(0.4)} =0.7565

Now, we compute the work:

W=\frac{P_2V_2-P_1V_1}{1-n} =\frac{2bar*0.04m^3-1bar*0.1m^3}{1-0.7565} \\\\W=-0.082bar*m^3*\frac{1x10^2kPa}{1bar}\\ \\W=-8.2kPa

Regards.

8 0
4 years ago
HURRY I"M BEING TIMED!!!! if an unknown solution has a pH of 2. how would you classify this solution?
Sergeu [11.5K]
An acid, acids have a pH less than 7
7 0
3 years ago
Please answer 14 will give brainliest
rosijanka [135]

Answer:

I think it's alkali metals

4 0
3 years ago
Read 2 more answers
Q1. Briefly explain why the Zeff experienced by a valence electron in Cl is larger than in Mg. Q2. Briefly explain why the Zeff
Inessa05 [86]

Answer:

See explanation

Explanation:

Q1:

Chlorine has 17 protons while magnesium has only 12 protons. Recall that the Zeff depends on the size of the nuclear charge. The greater the size of the nuclear charge, the larger the Zeff experienced by a valence electron.

Q2:

The larger the Zeff, the smaller the atomic radius. Since the valence electrons of Cl experience a greater Zeff than those of Mg due to greater size of the nuclear charge, the atomic radius of chlorine will be smaller than that of Mg.

Q3:

The radius of an atom increases as the value of the principal quantum number (n) increases down the group due to addition of more shells. The greater the number of shells added, the greater the principal quantum number (n) and the greater the atomic radius, hence the answer.

5 0
3 years ago
Match the measurement with the correct number of significant digits:
alina1380 [7]
What are you measuring
5 0
4 years ago
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