Answer:
What’s the freaking question G ??!?
 
        
                    
             
        
        
        
Answer:     
Step-by-step explanation:
uhh
 
        
             
        
        
        
F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
        
             
        
        
        
Answer:
P = 57°
Step-by-step explanation:
Given the following :
PQ = 17
QR = 15
PR = 14
Using the cosine formula since the length of the three sides are given:
a2 = b2 + c2 – 2bccos(A)
To find P:
QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)
15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)
225 = 289 + 196 - 476 cosP
476*CosP = 485 - 225
476*CosP = 260
CosP = 260/476
CosP = 0.5462184
P = Cos^-1(0.5462184)
P = 56.892029
P = 57°
 
        
             
        
        
        
There are  156 rows of trees altogether.
<u>Step-by-step explanation:</u>
Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.
Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious. 
Number of rows of Royal Gala=18

For 11 rows of red delicious,they plant 7 rows of yellow delicious.
Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.
For 66 rows of red delicious there would be 

For 11 rows of red delicious,they plant 5 rows of Braeburn
for 1 row of red delicious,they would plant 5/11 rows of Braeburn.
For 11 rows of red delicious,they would plant

Total rows of trees=66+42+30+18=156