3 years ago

Equations of Exponential Functions

Mathematics

1 answer:

puteri [66]3 years ago

6 0

Answer:

D. 46.5%

Step-by-step explanation:

I calculated it logically

You might be interested in

Use a table of values to estimate the value of the limit. Confirm your result graphically by graphing the function with a graphi

il63 [147K]

Hello,

$\lim_{x \to 0}\dfrac{ \sqrt{x+25}-5}{x}\\\\$

$=\lim_{x \to 0}\dfrac{(\sqrt{x+25}-5)*(\sqrt{x+25}+5)}{x*(\sqrt{x+25}+5)}\\\\$

$=\lim_{x \to 0}\dfrac{x+25-25)}{x*(\sqrt{x+25}+5)}\\\\$

$=\dfrac{1}{10}$

4 0

3 years ago

Below is the graph of y=x^3. Translate it to make it the graph of y=(x-4)^3-1

Vadim26 [7]

Answer:7=0.5 |x-4| -3

+3 +3

10=0.5 |x-4|

10/0.5=0.5/0.5 |x-4|

20=|x-4|

-20=x-4 20=x-4

+4 +4 +4 +4

-16=x 24=x

The answers are -16=x and 24=x

Hope this helps, an if it pleases you put as the brainliest answer

8 0

3 years ago

Read 2 more answers

If 3x4+2=56.8, what is the value of x? x≈6.708 x≈−4.323 x≈−2.891 x≈−2.059

Sphinxa [80]

Answer:

d. x= -2.059

Step-by-step explanation:

let me know if this is incorrect

5 0

3 years ago

The height of a ball (in feet) after t seconds is given by the quadratic function h=-16(t-5)^2+116

Dmitriy789 [7]

Check the picture below, so pretty much reaches its maximum height at the vertex, now let's take a peek at the equation above hmmmm

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h(t)=-16(t ~~ - ~~ \stackrel{h}{5})^2~~ + ~~\stackrel{k}{116}~\hfill \underset{maximum~height}{\stackrel{vertex}{(5~~,~~\underset{\uparrow }{116})}}$

6 0

2 years ago

Read 2 more answers

Find the value of x.

34kurt

56 is that helpful or no

8 0

3 years ago