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natka813 [3]
4 years ago
12

How many electrons are transferred in the ionic bond between sodium and chlorine in nacl?

Chemistry
2 answers:
serious [3.7K]4 years ago
8 0
From the periodic table, we can find that:
Sodium has 11 electrons with a configuration of (2,8,1)
Chlorine has 17 electrons with a configuration of (2,8,7)

Based on this, we can see that sodium needs to lose one electron to become stable with valence shell having 8 electrons.
On the other hand, chlorine needs to gain one electron to become stable with valence shell having 8 electrons.

In sodium chloride, the sodium donates this one electron to chlorine forming an ionic bond so they both become stable.
saw5 [17]4 years ago
5 0

Answer:

1

Explanation:

Just got it right on the quiz.

That is the exchange to fill.

Hope this helps.

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At which temperature would a reaction with H -92 kJ/mol, S -0.199 kJ/(mol-K) be spontaneous? A.600k B.500k C.400k D.700k
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Given information : H = -92 KJ/mol and S = -0.199 KJ/(mol.K)

At equilibrium G = 0

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For spontaneous reaction : \triangle G = negative (-)

For non-spontaneous reaction : \triangle G = positive (+)

We can find the temperature using the formula for Gibbs free energy which is:

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\triangle G = \bigtriangleup H - T\bigtriangleup S

Since reaction should be spontaneous that means \triangle G should be negative , so the above formula can be written as :

\triangle G < \bigtriangleup H - T\bigtriangleup S

On rearranging the above formula we get :

0 < \bigtriangleup H - T\bigtriangleup S

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T < (\frac{-92}{-0.199})\times (\frac{KJ}{mol})\times (\frac{mol.K}{KJ})

T < 462.3 K

For the reaction to be spontaneous , T should be less than 462.3 K, so out of given option , C is correct which is 400 K.

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