How much energy is released when 37.8 g of water freezes? the heat of fusion for water is 6.02 kj/mol. the amount of heat energy

Question

Llana [10]

4 years ago

10

How much energy is released when 37.8 g of water freezes? the heat of fusion for water is 6.02 kj/mol. the amount of heat energy

released = kj?

Chemistry

1 answer:

Aleksandr [31] · Answer 1 · 2021-11-15T21:14:45+03:00

Answer is: 12.642 kJ of heat <span>is released.
</span>m(H₂O) = 37.8 g; mass of water.
M(H₂O) = 2 · 1 g/mol + 16 g/mo = 18 g/mol.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 37.8 g ÷ 18 g/mol.
n(H₂O) = 2,1 mol; amount of substance.
ΔHfus = 6.02 kJ/mol; <span>the heat of fusion.
</span>Q = n(H₂O) · ΔHfus.
Q = 2.1 mol · 6.02 kJ/mol.
Q = 12.642 kJ.