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Goshia [24]
3 years ago
12

2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele

ased into a 10.0L reaction vessel at a temperature of 33.6°C, what will be the pressure inside the reaction vessel?
Chemistry
1 answer:
Umnica [9.8K]3 years ago
4 0

Answer: n∗R=22+273.15/4.2∗5n

P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10

Explanation:

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Match each statement with one of these terms.
skelet666 [1.2K]

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

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2 years ago
Hello :) for qn 3 , I got 0.01 mol but I’m not sure if it’s correct :/ I need help , thanks!
damaskus [11]

Answer:

0.05 dm³

Explanation:

Please see the attached picture for full solution.

The question is asking for the volume of H₂SO₄, so we need to find the number of moles of KOH then the number of moles of H₂SO₄. (Using mole ratio from the balanced equation) Also, potassium hydroxide is KOH not K₂SO₄ :)

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Ethanol has a Kb of 1.22 Degrees C/m and usually boils at 78.4 Degrees Celcius. How many mol of an nonionizing solute would need
Gala2k [10]

Answer:

0.3097 moles of an nonionizing solute would need to be added.

Explanation:

Molal elevation constant = k_b=1.22^oC/m

Normal boiling point of ethanol = T_o=78.4^oC

Boiling of solution =T_b=86.30^oC

Moles of nonionizing solute = n

Mass of ethanol (solvent) = 47.84 g

Elevation boiling point:

\Delta T_b=T_b-T_o

\Delta T_b=86.30^oC-78.4^oC=7.9^oC

\Delta T_b=K_b\times  m

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7.9^oC=1.22^oC/m\times \frac{n}{0.04784 kg}

n = 0.3097 mol

0.3097 moles of an nonionizing solute would need to be added.

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3 years ago
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