Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.
For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.
<h3>Binomial probability distribution
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The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- One in ten students are named Joe, hence
.
- There are 15 students in the class, hence
.
The probability that at least one of them is named Joe is:

In which:


Then:

0.7941 = 79.41% probability that at least one of them is named Joe.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
A trick I did when it comes to multiplying by 10, is just add a 0 at the end of the number your multiplying. Try for yourself!
let's recall that to find the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

Answer:
26.2% of smokers,when given this treatment, would refrain from smoking for at least 6 months.
Step-by-step explanation:
In this problem, we have that:
935 smokers received the treatment(nicotine patch).
After 6 months, 245 of them were not smoking.
Assuming it is reasonable to regard this sample as representative of all smokers, estimate the percentage of all smokers who, when given this treatment, would refrain from smoking for at least 6 months.
This percentage is 245/935 = 0.2620.
26% of smokers,when given this treatment, would refrain from smoking for at least 6 months.