Answer:
They will have values in common
Step-by-step explanation: I GUESSED
Since you have the length and the area, you can assume the width
1496/44 = Width Because Area = L * W
Width = 34
So this is a ratio problem
44/11 = ratio
So, the ratio is 4:1
So since we have the width, we can divide the width of the school banner by 4 because of the scale
34/4 = 8.5 = width of the sign
The area of the sign is 8.5*11 = 93.5
and the perimeter is just that,
8.5 * 2 + 11*2 = 39
Perimeter = 39 inches
Area = 93.5 inches²
Answer: The guage block height is 4.98 m
The base of the right triangle that is formed is 7.3784 m
The last angle in the triangle is 56 degrees
Step-by-step explanation:
Redraw the triangle formed in the picture and use H for the hypotenuse, O for the block height, and A for the base. Now we can use trig (SOHCAHTOA) to find the answaers.
Using sine, we can first find the gauge block height, O (Opposite). Given the Hypotenuse (H) is 8.9 m, we can use the definition of the sine of an angle to find the height, O.
Sine(34) = Opposite/Hypotenuse (O/H), or O = H*Sine(34)
O = (8.9)*(0.5592)
O = 4.98 m, the height of the gauge block,
The base of the triangle, A, can be determined with cosine.
Cosine(34) = A/O, or A = Cosine(34)*O
A = (0.82904)*(8.9)
A = 7.3784 m
The sum of all angles in a triangle is 180 degrees.
180 = X + 34 + 90
X = 56 degrees
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