Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Answer
the answer is P=7.8
Step-by-step explanation:
P=14.7e -0.21x
X=14.7e (-0.63)
take the natrual log of both sides
1n(P)=1n(14.7e(-.63)
1n(P)=1n(14.7)-.63
(because ln(e^a) = a)
1n(P)=2.688 - .63
1n(P)=2.058
P=e 2.058
P=7.8
Answer:
he would have to pick 1,2,3 or 5...so that is 4/6 chance
if you need the percentage (im not sure if its right) it would be 76%
Answer:
-3 f
ithink
Step-by-step explanation: