Answer:
After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
Step-by-step explanation:
We need to complete the square:
x^2 − 4x − 8 = 0
x^2 -2(x)(2)+(2)^2 -8 -4 =0
(x^2 -4x +4) - 12 = 0
(x-2)^2 -12 =0
Now, finding the value of x
(x-2)^2 -12 =0
(x-2)^2 = 12
taking square root on both sides

So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
The answer is 20in. You multiply 4 by 5 because 5x5 is 25 so the answer is 20
Answer:
∠EGF = 65°
Step-by-step explanation:
Since EF = EG the triangle is isosceles and the base angles are equal, that is
∠EGF = ∠GEF
∠EGF =
=
= 65°
Answer:
b
Step-by-step explanation:
Answer:
1st= 2 1/2
2nd= ???
3rd= 1/3
4th= 1/7
5th= 5/144
Step-by-step explanation: