Problem 2: Suppose that a 3 Ã 5 coefficient matrix A has a pivot in each of the three rows. If we augment A to represent a linea
1 answer:
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Answer:
30
Step-by-step explanation:
For the minimum free throws, he must put every throw to the basket.
So, let n be the number of throws for Tuesday, in which all the throws are successful.
So, over both the days, total free throws he makes= 15+n.
Total numbers of throws that went in the basket= 6+n.
As he wants at least 80% of his balls to go in the basket.
So, 6+n is greater than or equal to 809% of 15+n, i.e
Hence, the minimum number of free throws required on Tuesday to reach his goal is 30.
Answer:
y + 4 = 4(x-4)
Step-by-step explanation:
Use the point slope form of a line to write the equation by substituting m = 4 and the point (4,-4).